Python Exercise 2 - "Faulty Calculator"

 Python Exercise 2 - 

"Faulty Calculator"

Q:    Design a calculator which will correctly solve all the problems except the following ones:

  45 * 3 = 555, 56+9 = 77, 56/6 = 4

 Your program should take operator  & the two numbers as input from the user and then return the result.

Solution:

# Input Part
Calculator_On = True
print('Welcome, Your Calculator is ready to serve you !')
while (Calculator_On == True):
    x = int(input('Please enter First number : '))
    y = int(input('Please enter Second number : '))
    operator = input('Please Select Operator from these {*,/,+,-} : ')

    # Output Part
    if (operator == '*'):
        if (x == 45 and y == 3):
            print('Output : ', 555)
        else:
            print('Output : ', x * y)
    elif (operator == '/'):
        if (x == 56 and y == 6):
            print('Output : ', 4)
        else:
            print('Output : ', x / y)
    elif (operator == '+'):
        if (x == 56 and y == 9):
            print('Output : ', 77)
        else:
            print('Output : ', x + y)
    elif (operator == '-'):
        print('Output : ', x - y)

    print(' Do you want to calculate again?', '\n', 'Please type 1 for YES or 0 for NO.')
    Calculator_On = int(input())
    if (Calculator_On == False):
        print('Thank you, Hope you will use me again !')